Tutorial - Solving logarithmic equations ex 10, log(2x)+log(x-5)=2

Tutorial - Solving logarithmic equations ex 10, log(2x)+log(x-5)=2

http://www.freemathvideos.com In this video playlist you will explore how to solve logarithmic equations. To solve logarithmic equations it is important to first simplify your equation so that you either have an isolated logarithmic equation on one side or a logarithm equal to another logarithm. To simplify a logarithmic expression we will use the properties of logarithms to condense our expression to one logarithm. Then we will use inverse operations to isolate the logarithmic expression. Once we have a logarithm isolated we can convert the equation to exponential form to solve for the variable. If we have an equation where a logarithm is equal to another logarithm then we will use the one to one property remove the logarithms from the equation and solve the equation. log(2x)+log(x-5)=2

Simplify 2(log 2x - log y) - (log 3 + 2log 5)

Simplify 2(log 2x - log y) - (log 3 + 2log 5)

Visit our website: https://www.MinuteMathTutor.com Consider supporting us on Patreon... https://www.patreon.com/MinuteMath Properties of Logarithms Simplify 2(log 2x - log y) - (log 3 + 2log 5) Follow us for... Tweets: https://twitter.com/minutemath Instagram: @MinuteMath Facebook: https://www.facebook.com/MinuteMath/ Vine: MinuteMath TeachersPayTeachers: MinuteMath

Derivatives of Exponential Functions & Logarithmic Differentiation Calculus lnx, e^2x, x^x, x^sinx

Derivatives of Exponential Functions & Logarithmic Differentiation Calculus  lnx, e^2x, x^x, x^sinx

This calculus video tutorial shows you how to find the derivative of exponential and logarithmic functions. it also shows you how to perform logarithmic differentiation. It contains plenty of examples and practice problems that involve differentiation techniques such as the power rule, product rule, quotient rule, and the chain rule. Calculus Video Playlist: https://www.youtube.com/watch?v=rCxi-O79sVo&t=25s&index=1&list=PL0o_zxa4K1BVKErFko9je9IBZ0hXWXVtV Algebra Online Course: https://www.udemy.com/algebracourse7245/learn/v4/content Access to Premium Videos: https://www.patreon.com/MathScienceTutor Here is a list of topics: 1. Derivatives of Exponential Functions - e^x, e^2x, e^3x, e^x^2, e^2, e^u. 2. Exponential & Trigonometric Functions - e^sinx and e^cos(2x) 3. Derivatives of Natural Logarithmic Functions - lnx, ln(x^2), ln(2x), ln(x+1) 4. Product Rule - xe^x, xlnx, and x^2lnx 5. Quotient Rule - lnx/x 6. Chain Rule with Natural Logs - ln(lnx), ln(ln(lnx)) 7. Chain Rule - Logarithmic and Trig Functions - ln(cosx) and ln(sinx) 8. Derivatives of Standard Logarithmic Functions - log(1-x), log(2x), and log(x^2) 9. Derivatives of Exponential Functions without base e - 2^x, 4^x^2, and 7^(4x-x^2) 10. Logarithmic Differentiation Process & Equation / Formula 11. x^sinx, x^x, and x^lnx

log(2x) - log(x-3) = 1

log(2x) - log(x-3) = 1

log(2x) - log(x-3) = 1

Solving Logarithmic Equations

Solving Logarithmic Equations

From Thinkwell's College Algebra Chapter 6 Exponential and Logarithmic Functions, Subchapter 6.4 Exponential and Logarithmic Equations

Solving Logarithmic Equations With Logs on Both Sides, Ln, e, Square Roots - Algebra

Solving Logarithmic Equations With Logs on Both Sides, Ln, e, Square Roots - Algebra

This algebra video tutorial focuses on solving logarithmic equations with logs on both sides, with ln, e, and with square roots. It discusses the properties of logs that you need to know to combine two logs into a single log and how to convert from logarithmic to exponential form. Here is a list of topics: 1. How to solve logarithmic equations with logs on both sides 2. How to convert from logarithmic form to exponential form 3. Solving logarithmic equations with square roots 4. Logarithmic equations with e and ln 5. How to solve logarithmic equations without the use of a calculator 6. Addition and Subtraction Properties of Logarithms 7. Logarithms Rules - Review / Tutorial

Introduction to Logarithms

Introduction to Logarithms

An introduction to logarithms About Khan Academy: Khan Academy is a nonprofit with a mission to provide a free, world-class education for anyone, anywhere. We believe learners of all ages should have unlimited access to free educational content they can master at their own pace. We use intelligent software, deep data analytics and intuitive user interfaces to help students and teachers around the world. Our resources cover preschool through early college education, including math, biology, chemistry, physics, economics, finance, history, grammar and more. We offer free personalized SAT test prep in partnership with the test developer, the College Board. Khan Academy has been translated into dozens of languages, and 100 million people use our platform worldwide every year. For more information, visit www.khanacademy.org, join us on Facebook or follow us on Twitter at @khanacademy. And remember, you can learn anything.

Solve log(x+1)-log(x)=log(2x)

Solve log(x+1)-log(x)=log(2x)

Logs

Tutorial - Solving logarithmic equations ex 12, log5 - log2x=1

Tutorial - Solving logarithmic equations ex 12, log5 - log2x=1

http://www.freemathvideos.com In this video playlist you will explore how to solve logarithmic equations. To solve logarithmic equations it is important to first simplify your equation so that you either have an isolated logarithmic equation on one side or a logarithm equal to another logarithm. To simplify a logarithmic expression we will use the properties of logarithms to condense our expression to one logarithm. Then we will use inverse operations to isolate the logarithmic expression. Once we have a logarithm isolated we can convert the equation to exponential form to solve for the variable. If we have an equation where a logarithm is equal to another logarithm then we will use the one to one property remove the logarithms from the equation and solve the equation. log5 - log2x=1

`log(x)-log(2x-3)=1`, Then `x`

`log(x)-log(2x-3)=1`, Then `x`

To ask Unlimited Maths doubts download Doubtnut from - https://goo.gl/9WZjCW `log(x)-log(2x-3)=1`, Then `x`

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